https://www.acmicpc.net/problem/24479

코드설명

DFS(깊이우선탐색)을 활용합니다.

 

문제에서 주어진 의사코드대로 구현하면 되고, 

행렬로 그래프를 표현할시 메모리 초과가 발생하므로, LinkedList 형식으로 구현합니다.

코드

package Main;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Collections;
import java.util.StringTokenizer;
public class Main {
static int N, M, S, P, K, A, B, X, R;
// static int answer = 0;
static int[] answer;
static ArrayList<Integer>[] arr = new ArrayList[100001];
static boolean[] visited = new boolean[100001];
static int rank = 1;
public static void main(String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st = new StringTokenizer(br.readLine());
N = Integer.parseInt(st.nextToken());
M = Integer.parseInt(st.nextToken());
R = Integer.parseInt(st.nextToken());
answer = new int[N];
for(int i=0;i<100001; i++) {
arr[i] = new ArrayList<Integer>();
}
for(int i=0;i<M; i++) {
st = new StringTokenizer(br.readLine());
int u = Integer.parseInt(st.nextToken()) - 1;
int v = Integer.parseInt(st.nextToken()) - 1;
arr[u].add(v);
arr[v].add(u);
}
for(int i=0;i<N;i++) {
Collections.sort(arr[i]);
}
DFS(R-1);
for(int i=0;i<N;i++) {
System.out.println(answer[i]);
}
}
static void DFS(int now) {
visited[now] = true;
answer[now] = rank++;
for(int next =0; next < arr[now].size(); next++) {
int nextNode = arr[now].get(next);
if(visited[nextNode] == true) continue;
DFS(nextNode);
}
}
}

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